Inequality reasoning for Bank Exams
প্রিয় পাঠক, ব্যাঙ্কিং পরীক্ষার উপযোগী রিজনিং ইনইকুয়ালিটি প্রশ্ন (Inequality Reasoning for Bank Exams )এখানে দেওয়া হলো।
ব্যাঙ্কিং রিজনিং-ইনইকুয়ালিটি-সেট -২
Directions: -In these questions, relationship between different elements is shown in the statements. The statements are followed by conclusions. Study the conclusions based on the given statements and give answer:
a) If neither conclusion I nor II is true
b) If either conclusion I or II is true
c) If only conclusions II is true
d) If both conclusions I & II are true
e) If only conclusions I is true
1) Statements:
N ≤ P, P≥ Z, Z > H, H=D
Conclusions:
I) P > D II) Z >D
2) Statements:
R > O, O ≥ T, T > U, U ≤ M
Conclusions:
I) M ≥ T II) R < M
3) Statements:
H ≤ R, R < W, W= F, F ≤ J
Conclusions:
I) J > H II) H < W
4) Statements:
L ≤ V, V > E, E= U, U ≥ B
Conclusions:
I) B >V II) L ≥ B
5) Statements:
F ≥ j, J ≤ R, R = L , L < M
Conclusions:
I) M > J II) F < R
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Directions: – Read the following information/statement carefully and answer the questions:
6) Statements:
C ≥ O = M < U ≤ N <D
Conclusions:
I) O<D II) C > N
7) Statements:
P > L = A ≥ C = E
Conclusions:
I) E ≤ L II) P >C
8) Statements:
S > T ≤ A = I; L ≥ A
Conclusions:
I) L ≥ T II) A> S
9) Statements:
S > T ≤ A = I; L ≥ A
Conclusions:
I) S > L II) I ≤ L
10) Statements:
N ≤ U < M = B ≥ E > R
Conclusions:
I) N ≤ R II) E ≤ U
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Inequality reasoning for Bank Exams-ANSWERS
1.d) Combining all these statement,
we get N ≤ P ≥ Z >H= D
Thus P > D is true and Z >D is true.
Hence both conclusion I & II true.
2.a) combining all these statements,
we get R > O ≥ T > U ≤ M
We can’t compare R & M
Hence II is not true.
Again, we can’t compare M & T.
Hence I does not true
3.d) Combining all these statements, we get
H ≤ R < W = F ≤ J
Thus H < J or J > H is true.
Hence I true. Again H < W is true.
Hence I true
Again H < W is true.
Hence II is true
4.a) Combining all these statements, we get
L ≤ V <E =U ≥ B
We can’t compare B & V or L & B.
Hence I & II are not true.
5.e) Combining all these statements, we get
F ≥ J ≤ R = L < M
Thus we can’t F<R
Hence II is not true.
Again J <M or M > J is true.
Hence I is true
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6.e) O < D is true.
Again we can’t compare C & N.
Hence II is not true
7.d) L ≥ E or E ≥ l is true.
Hence conclusion I is true
Again, P > C is true. Hence conclusion II is true
8.e) Combining all these statements, we get
S > T ≤ A ≤ L
Thus T ≤ l or L ≥ T is true.
Hence conclusion I is true. But we cannot compare S and A
Hence conclusion II is not true
9.c) Combining all these statements, we get
S > T ≤A = I ≤L
Thus we cannot compare S and L
Hence conclusion I is not true.
Again I ≤ l is true
Hence conclusion II is true
10.a) We can’t compare N and R. Hence conclusion I is no true.
Again, we cannot compare U and E.
Hence II also is not true.
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